1[1+c]-[2+c]=10

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Solution for 1[1+c]-[2+c]=10 equation: 


Simplifying
1[1 + c] + -1[2 + c] = 10
[1 * 1 + c * 1] + -1[2 + c] = 10
[1 + 1c] + -1[2 + c] = 10
1 + 1c + [2 * -1 + c * -1] = 10
1 + 1c + [-2 + -1c] = 10

Reorder the terms:
1 + -2 + 1c + -1c = 10

Combine like terms: 1 + -2 = -1
-1 + 1c + -1c = 10

Combine like terms: 1c + -1c = 0
-1 + 0 = 10
-1 = 10

Solving
-1 = 10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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